By John Doe November 7, 2024
Summary: In this article, you will learn how to calculate percentages over different groups in PostgreSQL.
Table of Contents
Introduction
Traditionally, calculating percentages over a set of individual contributions was an ungainly business:
- First calculate the denominator of the percentage,
- Then join that denominator back to the original table to calculate the percentage.
This requires two passes of the table: once for the denominator and once for the percentage. For BI queries over large tables (that is, for most BI queries) more passes over the table slow performance significantly. Also, the SQL was really ugly!
With modern PostgreSQL, you can calculate complex percentages over different groups in a single pass, using “window functions”.
Example Data
Here’s our pretend data, a small table of seven musicians who perform in two bands.
CREATE TABLE musicians (
band text,
name text,
earnings numeric(10,2)
);
INSERT INTO musicians VALUES
('PPM', 'Paul', 2.2),
('PPM', 'Peter', 4.5),
('PPM', 'Mary', 1.1),
('CSNY', 'Crosby', 4.2),
('CSNY', 'Stills', 6.3),
('CSNY', 'Nash', 0.3),
('CSNY', 'Young', 2.2);
Percentage Total Earnings per Musician
Back in the “olden days”, before WITH statements and window functions, the query might look like this:
SELECT
band, name,
round(100 * earnings/sums.sum,1) AS percent
FROM musicians
CROSS JOIN (
SELECT Sum(earnings)
FROM musicians
) AS sums
ORDER BY percent;
With modern PostgreSQL, we can use “window functions” to calculate the denominator of our percentage on-the-fly. If you look up window functions in the documentation you will find some specific window-only functions like row_number()
, but you’ll also find that the old aggregate functions like sum()
can be used in a windowing mode.
SELECT
band, name,
round(100 * earnings /
Sum(earnings) OVER (),
1) AS percent
FROM musicians
ORDER BY percent;
Here, we get a sum of all earnings, by using the sum()
function with the OVER
keyword to indicate a windowing context.
Since we provide no restrictions on OVER
the effect is a sum over all rows in the result relation. Which is what we need!
Percentage of Band Earnings per Musician
Percentage earnings over all earnings is only one way to slice up the earnings pie: maybe we want to know which musicians made the most money relative to their band earnings?
Doing this the old fashioned way, the SQL is getting a lot hairier!
WITH sums AS (
SELECT Sum(earnings), band
FROM musicians
GROUP BY band
)
SELECT
band, name,
round(100 * earnings/sums.sum, 1) AS percent
FROM musicians
JOIN sums USING (band)
ORDER BY band, percent;
With the window function, on the other hand, we just need to change the characteristic of the denominator. Rather than a sum of all earnings, we want the sum calculated per band, which we get by adding a PARTITION
to the OVER
clause of the window function.
SELECT
band, name,
round(100 * earnings /
Sum(earnings) OVER (PARTITION BY band),
1) AS percent
FROM musicians
ORDER BY band, percent;
Percentage of Total Earnings per Band
Finally, for completeness, here’s the single-scan approach to getting the per-band percentage of total earnings:
SELECT
band,
round(100 * earnings /
Sum(earnings) OVER (),
1) AS percent
FROM (
SELECT band,
Sum(earnings) AS earnings
FROM musicians
GROUP BY band
) bands;
Note that I’ve been forced into using a sub-query here, because embedding a window query within an aggregate is not allowed.
However, if you check the EXPLAIN
for this query, you’ll find it still only has a single scan of the main data table, which is mostly what we are trying to avoid, since these kind of BI queries are usually run against very large fact tables, and scans are the expensive bit.